A) \[\frac{H({{n}_{1}}+{{n}_{2}}+{{n}_{3}}+{{n}_{4}})}{4}\]
B) \[\frac{H\left( \frac{1}{{{n}_{1}}}+\frac{1}{{{n}_{2}}}+\frac{1}{{{n}_{3}}}+\frac{1}{{{n}_{4}}} \right)}{4}\]
C) \[\frac{({{n}_{1}}+{{n}_{2}}+{{n}_{3}}+{{n}_{4}})}{4H}\]
D) \[\frac{H\left( \frac{1}{{{n}_{1}}}+\frac{1}{{{n}_{2}}}+\frac{1}{{{n}_{3}}}+\frac{1}{{{n}_{4}}} \right)}{2}\]
Correct Answer: B
Solution :
Apparent depth of bottom = \[\frac{H/4}{{{\mu }_{1}}}+\frac{H/4}{{{\mu }_{2}}}+\frac{H/4}{{{\mu }_{3}}}+\frac{H/4}{{{\mu }_{4}}}\] \[=\frac{H}{4}\left( \frac{1}{{{\mu }_{1}}}+\frac{1}{{{\mu }_{2}}}+\frac{1}{{{\mu }_{3}}}+\frac{1}{{{\mu }_{4}}} \right)\]You need to login to perform this action.
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