A) \[36.1{}^\circ \]
B) \[44.5{}^\circ \]
C) \[26.8{}^\circ \]
D) \[28.9{}^\circ \]
Correct Answer: D
Solution :
Refraction at air-oil point \[{{\mu }_{oil}}=\frac{\sin i}{\sin {{r}_{1}}}\] \[\therefore \]\[\sin {{r}_{1}}=\frac{\sin 40}{1.45}=0.443\] Refraction at oil-water point \[_{oil}{{\mu }_{water}}=\frac{\sin {{r}_{1}}}{\sin r}\] \[\therefore \] \[\frac{1.33}{1.45}=\frac{0.443}{\sin r}\] or \[\sin r=\]\[\frac{0.443\times 1.45}{1.33}\]Þ\[r={{28.9}^{o}}\]
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