Ethalpy at suction to the compressor | : | \[180\,\,kJ/kg\] |
Ethalpy at discharge from the compressor | : | \[210\,\,kJ/kg\] |
Enthalpy at exit from | : | \[80\,\,kJ/kg\] |
A) 5.33
B) 4.33
C) 3.33
D) 2.33
Correct Answer: C
Solution :
\[COP=\frac{{{h}_{1}}-{{h}_{4}}}{{{h}_{2}}-{{h}_{1}}}=\frac{180-80}{210-180}=\frac{100}{30}=3.33\]You need to login to perform this action.
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