• # question_answer In a vapour compression refrigeration cycle, following data are obtained: Ethalpy at suction to the compressor : $180\,\,kJ/kg$ Ethalpy at discharge from the compressor : $210\,\,kJ/kg$ Enthalpy at exit from : $80\,\,kJ/kg$ What is the C.O.P. of the cycle? A) 5.33                             B) 4.33C) 3.33                             D) 2.33

$COP=\frac{{{h}_{1}}-{{h}_{4}}}{{{h}_{2}}-{{h}_{1}}}=\frac{180-80}{210-180}=\frac{100}{30}=3.33$