A) 250 kJ/kg
B) 200 kJ/kg
C) 50 kJ/kg
D) 25 kJ/kg
Correct Answer: D
Solution :
Network of compression for the reversed Brayton refrigeration cycle\[=({{h}_{2}}-{{h}_{1}})-({{h}_{3}}-{{h}_{4}})\] Now, \[\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{{{T}_{3}}}{{{T}_{4}}}\] \[\therefore \,\,\,\,\,\,\,\,\,\,{{T}_{2}}=250\times \frac{300}{200}=375\,K\] Net work \[={{c}_{p}}[({{T}_{2}}-{{T}_{1}})-({{T}_{3}}-{{T}_{4}})]\] \[\,\,=0.1\,[(375-250)-(300-200)]\] \[\,\,=1[125-100=1\times 25=25\,kJ/kg]\]You need to login to perform this action.
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