A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: B
Solution :
\[\frac{a+bx}{a-bx}=\frac{b+cx}{b-cx}=\frac{c+dx}{c-dx}\] Applying componendo and dividendo, we get \[\frac{2a}{2bx}=\frac{2b}{2cx}=\frac{2c}{2dx}\]\[\Rightarrow \]\[{{b}^{2}}=ac\] and \[{{c}^{2}}=bd\] \[\Rightarrow \]\[a,\ b,\ c\]and \[b,\ c,\ d\] are in G.P. Therefore, \[a,\ b,\ c,\ d\] are in G.P.You need to login to perform this action.
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