A) A.P.
B) H.P.
C) G.P.
D) None of these
Correct Answer: C
Solution :
As \[p,\ q,\ r\] are in G.P. \[\therefore \]\[{{q}^{2}}=pr\] ?..(i) and \[a,\ b,\ c\] are also in G.P. \[\therefore \]\[{{b}^{2}}=ac\] ?..(ii) From (i) and (ii), \[{{q}^{2}}{{b}^{2}}=(pr)(ac)\]\[\Rightarrow \]\[{{(bq)}^{2}}=(cp)\ .\ (ar)\] Hence \[cp,\ bq,\ ar\] are in G.P.You need to login to perform this action.
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