A) \[n{{(2c)}^{1/n}}\]
B) \[(n+1)\,{{c}^{1/n}}\]
C) \[2n{{c}^{1/n}}\]
D) \[(n+1){{(2c)}^{1/n}}\]
Correct Answer: A
Solution :
A.M. \[\ge \] G.M. Þ \[\frac{{{a}_{1}}+{{a}_{2}}+....+{{a}_{n-1}}+2{{a}_{n}}}{n}\ge {{({{a}_{1}}.{{a}_{2,}}...{{a}_{n-1}}2{{a}_{n}})}^{\frac{1}{n}}}\ge {{(2c)}^{\frac{1}{n}}}\] \ Minimum value ofYou need to login to perform this action.
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