A) \[A>G\]
B) \[A\ne G\]
C) \[A=G\]
D) None of these
Correct Answer: C
Solution :
Sum of the roots of \[{{x}^{2}}-2ax+{{b}^{2}}=0\] is 2a, Therefore, A = A.M. of the roots = a. Product of the roots of \[{{x}^{2}}-2bx+{{a}^{2}}=0\,\,\text{is}\,\,\,{{a}^{2}}\] Therefore, G.M. of the roots is \[G=a\] Thus,\[A=G\]You need to login to perform this action.
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