A) \[\frac{A}{2}\]
B) A
C) 2 A
D) None of these
Correct Answer: C
Solution :
Let the two numbers be p and q. \[\therefore \,\,{{G}_{1}}={{p}^{2/3}}\,\,{{q}^{1/3}},\,\,{{G}_{2}}={{p}^{1/3}}\,\,\,{{q}^{2/3}}\] \[\therefore \,\frac{G_{1}^{2}}{{{G}_{2}}}+\frac{G_{2}^{2}}{{{G}_{1}}}=\frac{{{p}^{4/3}}\,\,{{q}^{2/3}}}{{{p}^{1/3}}\,\,{{q}^{2/3}}}+\frac{{{p}^{2/3}}\,{{q}^{4/3}}}{{{p}^{2/3}}\,{{q}^{1/3}}}\] \[=p+q=2\times \,\left( \frac{p+q}{2} \right)\,=2A\].You need to login to perform this action.
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