A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: B
Solution :
Given that \[a,\ b,\ c\] are in A.P. \[\Rightarrow b=\frac{a+c}{2}\] ?..(i) and \[{{b}^{2}}=ad\] ?.. (ii) Hence \[a,\ a-b,\ d-c\] are in G.P. because \[{{(a-b)}^{2}}={{a}^{2}}-2ab+{{b}^{2}}=a(a-2b)+ad\] \[=a(a-a-c)+ad=ad-ac\].You need to login to perform this action.
You will be redirected in
3 sec