A) \[3{{x}^{2}}+20x-17=0\]
B) \[17{{x}^{2}}-20x+3=0\]
C) \[17{{x}^{2}}+20x+3=0\]
D) None of these
Correct Answer: B
Solution :
Given equation is \[3{{x}^{2}}-20x+17=0\] Þ \[(x-1)(3x-17)=0\]Þ \[x=1,\,\,\frac{17}{3}\] Reciprocal roots are 1 and \[\frac{3}{17}\] \ Equation is \[{{x}^{2}}-\left( 1+\frac{3}{17} \right)\,x+\frac{3}{17}=0\] Þ \[17{{x}^{2}}-20x+3=0\].
You need to login to perform this action.
You will be redirected in
3 sec
