A) b
B) - b
C) \[1-b\]
D) \[b-1\]
Correct Answer: C
Solution :
Given equation \[{{x}^{2}}-a(x+1)-b=0\] Þ \[{{x}^{2}}-ax-a-b=0\]Þ \[\alpha +\beta =a,\alpha \beta =-(a+b)\] Now \[(\alpha +1)(\beta +1)=\alpha \beta +\alpha +\beta +1\] = \[-(a+b)+a+1=1-b\]You need to login to perform this action.
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