A) 3
B) 4
C) 2
D) 1
Correct Answer: A
Solution :
Given, \[{{3}^{2}}+a.3+3=0\]; \[a=-4\] Let roots of equation \[{{x}^{2}}-4x+b=0\] is \[\alpha \] and\[3\alpha \]. \[\alpha +3\alpha =4\]Þ \[4\alpha =4\]Þ \[\alpha =1\] Hence \[1-4+b=0\]Þ \[b=3\]You need to login to perform this action.
You will be redirected in
3 sec