A) 0
B) 1
C) \[{{\left( \frac{A}{a} \right)}^{2}}\]
D) \[{{\left( \frac{a}{A} \right)}^{2}}\]
Correct Answer: B
Solution :
\[{{(\alpha -\beta )}^{2}}={{(\alpha +\beta )}^{2}}-4\alpha \beta =({{b}^{2}}-4ac)/{{a}^{2}}\] ......(i) Also \[{{\left\{ (\alpha -k)-(\beta -k) \right\}}^{2}}\] = \[{{\{(\alpha -k)+(\beta -k)\}}^{2}}-4(\alpha -k)(\beta -k)\] =\[{{(-B/A)}^{2}}-4(C/A)\]\[=({{B}^{2}}-4AC)/{{A}^{2}}\] .....(ii) From (i) and (ii), \[({{b}^{2}}-4ac)/{{a}^{2}}=({{B}^{2}}-4AC)/{{A}^{2}}\] \ \[\frac{{{b}^{2}}-4AC}{{{b}^{2}}-4ac}={{\left( \frac{A}{a} \right)}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec