A) 1
B) 1/2
C) 2
D) -1
Correct Answer: B
Solution :
\[\frac{\sin \frac{A}{2}\sin \frac{C}{2}}{\sin \frac{B}{2}}=\sqrt{\frac{ac(s-b)(s-c)(s-b)(s-a)}{(s-a)(s-c)bc\times ab}}=\frac{s-b}{b}\] But a, b and c are in A. P. Þ \[2b=a+c\] Hence\[\frac{s-b}{b}=\frac{\frac{3b}{2}-b}{b}=\frac{1}{2}\].You need to login to perform this action.
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