A) \[\cos B=\frac{11}{6}\]
B) \[\cos B=\frac{7}{8}\]
C) \[AD=2.4\]
D) \[A{{D}^{2}}=2.5\]
Correct Answer: D
Solution :
\[\cos B=\frac{{{2}^{2}}+{{4}^{2}}-{{3}^{2}}}{2\times 2\times 4}=\frac{11}{16}\] \ \[\frac{11}{16}=\frac{{{2}^{2}}+{{2}^{2}}-A{{D}^{2}}}{2\times 2\times 2}\Rightarrow A{{D}^{2}}=2.5\].You need to login to perform this action.
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