A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{2}\]
C) \[\frac{2\pi }{3}\]
D) \[\frac{5\pi }{6}\]
Correct Answer: C
Solution :
It is given that area of \[\Delta ABC=\]Area of \[\Delta DEF\] Þ \[\frac{1}{2}(AB)(AC)\sin A=\frac{1}{2}(DE)(EF)\sin E\] Þ \[\sin A=\sin E\Rightarrow \sin 2E=\sin E\Rightarrow 2E=\pi -E\] Þ \[E=\frac{\pi }{3}\Rightarrow A=2E=\frac{2\pi }{3}\].You need to login to perform this action.
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