A) \[\tan A+\tan B=0\]
B) \[\tan B+\tan C=0\]
C) \[\tan A+2\tan C=0\]
D) \[\tan B.\tan C=1\]
Correct Answer: D
Solution :
\[\tan A=\tan (\pi -B-C)\]; \[\infty =-\frac{\tan B+\tan C}{1-\tan B\tan C}\] \[\Rightarrow 1-\tan B\tan C=0\] Þ \[\tan B\tan C=1\].You need to login to perform this action.
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