A) 1
B) 2
C) 4
D) None of these
Correct Answer: C
Solution :
From\[\Delta ADC\], \[\frac{\sin (y+z)}{DC}=\frac{\sin C}{AD}\] From \[\Delta ABD,\frac{\sin x}{BD}=\frac{\sin B}{AD}\] From \[\Delta AEC,\frac{\sin z}{EC}=\frac{\sin C}{AE}\] From \[\Delta ABE,\,\frac{\sin (x+y)}{BE}=\frac{\sin B}{AE}\]You need to login to perform this action.
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