A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{4}\]
C) \[\frac{\pi }{6}\]
D) None of these
Correct Answer: C
Solution :
Let\[A=6+\sqrt{12},b=\sqrt{48},c=\sqrt{24}\]. Clearly, c is the smallest side. Therefore, the smallest angle C is given by \[\cos C=\frac{{{a}^{2}}+{{b}^{2}}-{{c}^{2}}}{2ab}=\frac{\sqrt{3}}{2}\Rightarrow C=\frac{\pi }{6}\].
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