A) 0
B) 1
C) \[a+b+c\]
D) \[2(a+b+c)\]
Correct Answer: C
Solution :
\[(b+c)\cos A+(c+a)\cos B+(a+b)\cos C=a+b+c\] From expanding and collecting terms using projection rule, \[a=b\cos C+c\cos B\]etc.You need to login to perform this action.
You will be redirected in
3 sec