A) \[\frac{\pi }{6}\]
B) \[\frac{\pi }{4}\]
C) \[\frac{\pi }{3}\]
D) None of these
Correct Answer: C
Solution :
\[\cos B=\frac{{{c}^{2}}+{{a}^{2}}-{{b}^{2}}}{2ac}\Rightarrow \cos B=\frac{1}{2}i.e.,B=\frac{\pi }{3}\].You need to login to perform this action.
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