A) 30° with downstream
B) 60° with downstream
C) 120° with downstream
D) South
Correct Answer: C
Solution :
For shortest possible path man should swim with an angle (90+q) with downstream. From the fig, \[\sin \theta =\frac{{{v}_{r}}}{{{v}_{m}}}=\frac{5}{10}=\frac{1}{2}\] Þ \[\therefore \] q = 30° So angle with downstream = \[90{}^\circ +30{}^\circ =120{}^\circ \]You need to login to perform this action.
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