JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Relative Motion

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    An express train is moving with a velocity v1. Its driver finds another train is moving on the same track in the same direction with velocity v2. To escape collision, driver applies a retardation a on the train. the minimum time of escaping collision will be              [RPET 2002]

    A)                \[t=\frac{{{v}_{1}}-{{v}_{2}}}{a}\]                 

    B)                           \[{{t}_{1}}=\frac{v_{1}^{2}-v_{2}^{2}}{2}\]         

    C)                None                                

    D)                Both

    Correct Answer: A

    Solution :

                                                   As the trains are moving in the same direction. So the initial relative speed \[({{v}_{1}}-{{v}_{2}})\] and by applying retardation final relative speed becomes zero.               From \[v=u-at\] Þ \[0=({{v}_{1}}-{{v}_{2}})-at\] Þ \[t=\frac{{{v}_{1}}-{{v}_{2}}}{a}\]         


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