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JEE Main & Advanced Physics Elasticity Question Bank Rigidity Modulus

  • question_answer
    A cube of aluminium of sides 0.1 m is subjected to a shearing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be                               

    A) 0.02       

    B)                 0.1

    C)                 0.005     

    D)                 0.002

    Correct Answer: D

    Solution :

        Shearing strain \[\varphi =\frac{x}{L}=\frac{0.02cm}{10cm}\]\ \[\varphi =0.002\]


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