A) \[12{}^\circ \]
B) \[0.12{}^\circ \]
C) \[1.2{}^\circ \]
D) \[0.012{}^\circ \]
Correct Answer: B
Solution :
Angle of shear\[\varphi =\frac{r\theta }{L}\]\[=\frac{4\times {{10}^{-1}}}{100}\times {{30}^{o}}={{0.12}^{o}}\]
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