A) \[\theta /4\]
B) \[\theta /2\]
C) \[5\theta /6\]
D) \[8\theta /9\]
Correct Answer: D
Solution :
\[\tau =C.\theta =\frac{\pi \eta {{r}^{4}}\theta }{2L}=\]Constant \[\Rightarrow \frac{\pi \eta {{r}^{4}}(\theta -{{\theta }_{0}})}{2l}=\frac{\pi \eta {{(r/2)}^{4}}({{\theta }_{0}}-\theta ')}{2(l/2)}\] \[\Rightarrow \frac{(\theta -{{\theta }_{0}})}{2}=\frac{{{\theta }_{0}}}{16}\Rightarrow {{\theta }_{0}}=\frac{8}{9}\theta \]You need to login to perform this action.
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