A) \[3\times {{10}^{12}}\,N/{{m}^{2}}\]
B) \[2\times {{10}^{12}}\,N/{{m}^{2}}\]
C) \[{{10}^{12}}\,N/{{m}^{2}}\]
D) None of the above
Correct Answer: A
Solution :
\[Y=2\eta (1+\sigma )\] For no transverse strain (s = 0) \[Y=2\eta \Rightarrow \eta =\frac{Y}{2}=3\times {{10}^{12}}N/{{m}^{2}}\]
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