A) Zero
B) Infinity
C) \[2\times {{10}^{10}}\,N/{{m}^{2}}\]
D) \[3\times {{10}^{10}}\,N/{{m}^{2}}\]
Correct Answer: B
Solution :
\[Y=2\eta (1+\sigma )\] Þ \[3\eta =2\eta (1+\sigma )\]Þ\[\sigma =\frac{3}{2}-1=\frac{1}{2}\] Now substituting the value of s in the following expression. \[Y=3K(1-2\sigma )\] Þ \[K=\frac{Y}{3(1-2\sigma )}=\infty \]
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