A) 0
B) \[\frac{1}{\sqrt{x-1}}\]
C) \[2\sqrt{x-1}-5\]
D) None of these
Correct Answer: A
Solution :
From Rolle?s theorem in (1, 26), \[f(1)=f(26)=5\]. In given interval, function satisfy all the conditions of Rolle's theorem, therefore in [1, 26], at least, there is a point for which \[{f}'(x)=0\].
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