A) [0, 3]
B) [? 3, 0]
C) [1.5, 3]
D) For no interval
Correct Answer: D
Solution :
Here \[f(x)=\frac{{{x}^{2}}-3x}{x-1}\] Þ\[-\sin c=-\frac{2}{\pi }\Rightarrow c={{\sin }^{-1}}\left( \frac{2}{\pi } \right)\] Obviously, it is not derivable at \[x=1\] i.e., in \[(0,3)\] Also \[f(a)=f(b)\]does not hold for \[[-3,\,0]\] and [1. 5, 3] Hence the answer is .You need to login to perform this action.
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