A) 12
B) 2
C) 0
D) ? 12
Correct Answer: D
Solution :
\[(\mathbf{a}\times \mathbf{j})\,.\,(2\mathbf{j}-3\mathbf{k})=\mathbf{a}\,.\{\mathbf{j}\times (2\mathbf{j}-3\mathbf{k})\}\] \[=\mathbf{a}\,.\,\{-3(\mathbf{j}\times \mathbf{k})\}=-3(\mathbf{a}\,.\,\mathbf{i})=-12.\]
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