A) 3
B) 1
C) \[-3\lambda \]
D) \[3/\lambda \]
Correct Answer: B
Solution :
\[\frac{(b\times c)\,.\,(a+b+c)}{\lambda }\]\[=\frac{(b\times c)\,.\,a+(b\times c)\,.\,b+(b\times c)\,.\,c}{\lambda }\] \[=\frac{(b\times c)\,.\,a+0+0}{\lambda }\]\[=\frac{\lambda }{\lambda }=1\], (\[\because \]Given\[a\,.\,(b\times c)=\lambda =(b\times c)\,.\,a\]).You need to login to perform this action.
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