A) 0
B) \[\frac{\pi }{6}\]
C) \[\frac{\pi }{3}\]
D) \[\frac{\pi }{2}\]
Correct Answer: D
Solution :
\[\mathbf{a}+\mathbf{b}=-\,\mathbf{c}\]\[\Rightarrow \,\,|\mathbf{a}{{|}^{2}}+|\mathbf{b}{{|}^{2}}+2|\mathbf{a}||\mathbf{b}|\cos \theta =|\mathbf{c}{{|}^{2}}\] \[\Rightarrow \cos \theta =0\Rightarrow \theta =\frac{\pi }{2}.\]
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