A) \[\frac{\pi }{4}\]
B) \[\frac{\pi }{3}\]
C) \[\frac{\pi }{2}\]
D) \[\frac{2\pi }{3}\]
Correct Answer: B
Solution :
\[{{(\mathbf{a}-q\mathbf{b})}^{2}}=1=2-2\cos \Rightarrow \,\theta =60{}^\circ .\]
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