A) \[\sqrt{2}\]
B) \[\sqrt{3}\]
C) \[\frac{1}{\sqrt{3}}\]
D) 1
Correct Answer: B
Solution :
Let \[|\mathbf{a}|=1\] and \[|\mathbf{b}|=1\] Also \[|\mathbf{a}+\mathbf{b}{{|}^{2}}={{1}^{2}}\Rightarrow 1+1+2\cos \theta =1\]\[\Rightarrow \theta =120{}^\circ \] \[\therefore \,\,\,|\mathbf{a}-\mathbf{b}{{|}^{2}}=1+1-2\cos \theta =3\]\[\Rightarrow \,|\mathbf{a}-\mathbf{b}|\,=\sqrt{3}.\]
You need to login to perform this action.
You will be redirected in
3 sec
