A) \[\frac{4\,\mathbf{i}-\mathbf{j}}{\sqrt{17}}\]
B) \[\frac{-4\,\mathbf{i}+\mathbf{j}}{\sqrt{17}}\]
C) \[\frac{2\,\mathbf{i}-3\,\mathbf{j}}{\sqrt{13}}\]
D) \[\frac{-\,2\,\mathbf{i}+3\,\mathbf{j}}{\sqrt{13}}\]
Correct Answer: B
Solution :
\[\vec{L}=\mathbf{i}+4\mathbf{j}\] Therefore, vector perpendicular to \[\vec{L}=\lambda (4\mathbf{i}-\mathbf{j})\] \ Unit vector is \[\frac{4\mathbf{i}-\mathbf{j}}{\sqrt{17}}.\] But it points towards origin \[\therefore \] Required vector\[=\frac{-4\mathbf{i}+\mathbf{j}}{\sqrt{17}}.\]
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