A) 3
B) 4
C) 5
D) 6
Correct Answer: A
Solution :
Vectors \[a=2i+j+2k\] and \[\mathbf{b}=5i-3j+k\]. We know that the projection of b on \[a=\frac{b\,.\,a}{|\mathbf{a}|}=\frac{(2i+j+2k)\,.\,(5i-3j+k)}{\sqrt{{{(2)}^{2}}+{{(1)}^{2}}+{{(2)}^{2}}}}=\frac{10-3+2}{\sqrt{9}}=\frac{9}{3}=3.\]You need to login to perform this action.
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