A) \[\frac{(\mathbf{a}\,.\,\mathbf{b})\,\mathbf{a}}{\mathbf{b}\,.\,\mathbf{b}}\]
B) \[\frac{(\mathbf{a}\,.\,\mathbf{b})\,\mathbf{b}}{\mathbf{a}\,.\,\mathbf{a}}\]
C) \[\frac{(\mathbf{a}\,.\,\mathbf{b})\,\mathbf{b}}{\mathbf{a}\,.\,\mathbf{b}}\]
D) \[\frac{(\mathbf{a}\,.\,\mathbf{b})\,\mathbf{a}}{\mathbf{a}\,.\,\mathbf{a}}\]
Correct Answer: D
Solution :
\[(\mathbf{b}.\mathbf{\hat{a}})\mathbf{\hat{a}}=\left\{ \frac{(\mathbf{a}.\mathbf{b})}{|\mathbf{a}|} \right\}\mathbf{\hat{a}}=\frac{(\mathbf{a}.\mathbf{b})\mathbf{a}}{\mathbf{a}.\mathbf{a}}\].
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