A) \[{{t}_{1}}>{{t}_{2}}\]
B) \[{{t}_{2}}>{{t}_{1}}\]
C) \[{{t}_{1}}={{t}_{2}}\]
D) \[{{t}_{1}}>>{{t}_{2}}\]
Correct Answer: A
Solution :
For stationary lift \[{{t}_{1}}=\sqrt{\frac{2h}{g}}\] and when the lift is moving up with constant acceleration \[{{t}_{2}}=\sqrt{\frac{2h}{g+a}}\] \[\therefore \ \ {{t}_{1}}>{{t}_{2}}\]
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