2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. NLM, Friction, Circular Motion

JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A ball of mass 0.5 kg moving with a velocity of 2 m/sec strikes a wall normally and bounces back with the same speed. If the time of contact between the ball and the wall is one millisecond, the average force exerted by the wall on the ball is                            [CBSE PMT 1990]

    A)             2000 N

    B)               1000 N

    C)             5000 N

    D)             125 N

    Correct Answer: A

    Solution :

                    \[{{F}_{av}}=\frac{\Delta p}{\Delta t}=\frac{mv-(-mv)}{\Delta t}=\frac{2mv}{\Delta t}=\frac{2\times 0.5\times 2}{{{10}^{-3}}}\]= 2000 N


You need to login to perform this action.
You will be redirected in 3 sec spinner