JEE Main & Advanced
Physics
NLM, Friction, Circular Motion
Question Bank
Second Law of Motion
question_answer
Mass of a person sitting in a lift is 50 kg. If lift is coming down with a constant acceleration of 10 \[m/se{{c}^{2}}.\] Then the reading of spring balance will be \[(g=10m/se{{c}^{2}})\] [RPET 2003; Kerala PMT 2005]