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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A machine gun is mounted on a 2000 kg car on a horizontal frictionless surface. At some instant the gun fires bullets of mass 10 gm with a velocity of 500 m/sec with respect to the car. The number of bullets fired per second is ten. The average thrust on the system is                   [CPMT 1971]

    A)                         550 N             

    B)                         50 N            

    C)                         250 N             

    D)                         250 dyne

    Correct Answer: B

    Solution :

                                u = velocity of bullet             \[\frac{dm}{dt}=\]Mass thrown per second by the machine gun                = Mass of bullet × Number of bullet fired per second                \[=10\ g\times 10\ bullet/\sec \]\[=100\ g/\sec \ =\ 0.1\ kg/\sec \]             \[\therefore \] Thrust \[=\frac{udm}{dt}=500\times 0.1=50\ N\]            


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