JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    In the above question, the acceleration of the car will be         [CPMT 1971]            

    A)                              \[0.25\,m/{{\sec }^{2}}\]               

    B)                         \[2.5\,m/{{\sec }^{2}}\]            

    C)                         \[5.0\,m/{{\sec }^{2}}\]            

    D)                         \[0.025\,m/{{\sec }^{2}}\]          

    Correct Answer: D

    Solution :

                              Acceleration of the car \[=\frac{\text{Thrust on the car}}{\text{Mass of the car}}\]             \[=\frac{50}{2000}=\frac{1}{40}=0.025\ m/{{s}^{2}}\]


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