A) Proportional to \[{{t}^{2}}\]
B) A constant
C) Proportional to t
D) Inversely proportional to t
Correct Answer: C
Solution :
\[\vec{F}=\frac{d\vec{p}}{dt}\]= \[\frac{d}{dt}(a+b{{t}^{2}})=2bt\] i.e. \[F\propto t\]You need to login to perform this action.
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