A) \[3\,m/{{\sec }^{2}}\]
B) \[-3\,m/{{\sec }^{2}}\]
C) \[0.3\,m/{{\sec }^{2}}\]
D) \[-0.3\,m/{{\sec }^{2}}\]
Correct Answer: B
Solution :
\[\vec{a}=\frac{\overrightarrow{{{v}_{2}}}-\overrightarrow{{{v}_{1}}}}{t}=\frac{(-2)-(+10)}{4}=\frac{-12}{4}=-3\ m/{{s}^{2}}\]You need to login to perform this action.
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