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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A body of mass 4 kg weighs 4.8 kg when suspended in a moving lift. The acceleration of the lift is     [Manipal MEE 1995]            

    A)                         \[9.80\,m{{s}^{-2}}\] downwards               

    B)                         9.80\[m{{s}^{-2}}\] upwards          

    C)                         1.96\[m{{s}^{-2}}\] downwards                 

    D)                         1.96\[m{{s}^{-2}}\] upwards            

    Correct Answer: D

    Solution :

                                As the apparent weight increase therefore we can say that acceleration of the lift is in upward direction.             \[R=m(g+a)\]Þ\[4.8\ g=4(g+a)\]             Þ\[a=0.2g=1.96\ m/{{s}^{2}}\]


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