A) 3 : 1
B) 1 : 3
C) 1 : 2
D) 2 : 1
Correct Answer: A
Solution :
\[{{T}_{1}}=m\,(g+a)=1\times \left( g+\frac{g}{2} \right)=\frac{3g}{2}\] \[{{T}_{2}}=m\,(g-a)=1\times \left( g-\frac{g}{2} \right)=\frac{g}{2}\] \ \[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{3}{1}\]You need to login to perform this action.
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