JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    A force vector applied on a mass is represented as \[\vec{F}=6\hat{i}-8\hat{j}+10\hat{k}\] and accelerates with \[1\,m/{{s}^{2}}\]. What will be the mass of the body                                  [CBSE PMT 1996]

    A)                         \[10\sqrt{2}\,kg\]          

    B)                           \[2\sqrt{10}\,kg\]            

    C)                         10 kg               

    D)                         20 kg

    Correct Answer: A

    Solution :

                  \[m=\frac{F}{a}=\frac{\sqrt{{{6}^{2}}+{{8}^{2}}+{{10}^{2}}}}{1}=\sqrt{200}\]\[=10\sqrt{2}\,kg\]          


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